Monday, May 11, 2009

In a recent national survey, the mean weekly allowance for a 9 yr old is $3.65. A random sample of 45 nine yr

olds in Ohio revealed the mean allowance to be $ 3.65 with a standard deviation of .24. At the 0.5 level of significance , is there a difference in the mean allowances nationally and the mean allowances in Ohio for 9 years old.

In a recent national survey, the mean weekly allowance for a 9 yr old is $3.65. A random sample of 45 nine yr
Since n%26gt; large enough the sample is approximately normal.





Z = (3.65 - 3.65)/.24 = 0





Since the alternative hypothesis would intimate to me that the answer would be on either end... (i.e. not that you are testing whether Ohio is greater or less than average, but not average) that implies a 2-tailed test. Thus pushing your critical values away from zero and you accept the null hypothesis that Ohio is not different and the mean = 3.65

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