Monday, May 11, 2009

When a sample was surveyed on their preferance for yogurt flavor, 12 said vanilla and 8 said banana.?

The total group was 160. How many people wer ein the survey? What is the probability that a person prefers vanilla? Predict how many of othe 160 people prefer vanilla.

When a sample was surveyed on their preferance for yogurt flavor, 12 said vanilla and 8 said banana.?
20 in sample


12/20 prefer vanilla or 6/10 or 60% probability that a person prefers vanilla


60% of 160 = 96


( .6 * 160 )
Reply:Hell if i know, i don't even like yogurt.
Reply:Number of people on survey=12+8=20


P(V)=12/20=0.6


160*0.6=96
Reply:20 out of 160 people (1/8 or 12.5% of the group) were in the survey.


Probability that a person prefers vanilla =


12 / (12+8) = 3/5 = 0.6 or 60%.


This assumes that all the sample respondents answered either vanilla or banana (this is not stated explicitly).


Out of 160 people, we would expect 60%, or 96 people, to prefer vanilla.


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